You are given a 0-indexed array numsconsisting of positive integers, representing targets on a number line. You are also given an integer space.

You have a machine which can destroy targets. Seeding the machine with some nums[i]allows it to destroy all targets with values that can be represented as nums[i] + c * space, where cis any non-negative integer. You want to destroy the maximum number of targets in nums.

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Return the minimum value of nums[i]you can seed the machine with to destroy the maximum number of targets.

Example 1:

Input: nums = [3,7,8,1,1,5], space = 2

Output: 1

Explanation: If we seed the machine with nums[3], then we destroy all targets equal to 1,3,5,7,9,... In this case, we would destroy 5 total targets (all except for nums[2]). It is impossible to destroy more than 5 targets, so we return nums[3].

Example 2:

Input: nums = [1,3,5,2,4,6], space = 2

Output: 1

Explanation: Seeding the machine with nums[0], or nums[3] destroys 3 targets. It is not possible to destroy more than 3 targets.Since nums[0] is the minimal integer that can destroy 3 targets, we return 1.

Example 3:

Input: nums = [6,2,5], space = 100

Output: 2

Explanation: Whatever initial seed we select, we can only destroy 1 target. The minimal seed is nums[1].

Constraints:

1 <= nums.length <= 105

1 <= nums[i] <= 109

1 <= space <= 109

其实就是找数组中相对于space的余数中，哪个的余数最大，然后将最大的数量的那个余数找里面最小的值，返回即可的。

Runtime: 46 ms, faster than 82.22% of Java online submissions for Destroy Sequential Targets.

Memory Usage: 58.6 MB, less than 67.78% of Java online submissions for Destroy Sequential Targets.